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Thread: Measuring Belt Length in the Belt Drum

  1. Measuring Belt Length in the Belt Drum

    HOW Measuring the Belt length in the belt drum

    Dear Experts,


    PL forward the formula for to calculate the belt length from the DRUM.


    regards


    RK

  2. #2
    Very little information to go on here. I wish I could read minds but unfortunately I can't.

    I am assuming that you mean "How do you caculate the length of belt in a roll?" and not how much belt is around a pulley.

    I use these formulas:

    When thickness of the belt is known:
    L = ((D*D)-(C*C)) / (15.3*t)
    L = Length; D = Outside Diameter (inches); C = Inside Diameter (inches); t = belt thickness (inches)

    When wraps are known:
    L = ((D+C)*3.14*n) / 24
    n = Number of wraps in roll
    Last edited by Gary Blenkhorn; 29th April 2011 at 15:10.

  3. Dear Mr.RK2007,

    Imagine you are looking the edge of the unwound straightened belt.

    You will be seeing a very long rectangle.
    The area ( A ) of the rectangle is
    = Length of the belt ( L ) x thickness of the belt ( t ) ------- ( 1 )

    Now you have started rolling the belt and making a drum .
    Now again you are looking from the side.
    You measure Bigger diameter ( D ) of the drum & smaller diameter ( d ) where there is no belt.
    The area ( A ) remains same
    = Area of the Bigger diameter circle - Area of the smaller diameter circle ----- ( 2 )

    Equation ( 1 ) = Equation ( 2 )

    So Length of the belt in the belt drum = ( Area ) / ( Thickness of the belt )

    Word of caution : "The drum should be properly wound. It should not be loose & do not have many gaps in between the wraps."

    Regards,

  4. Quote Originally Posted by Gary Blenkhorn View Post
    Very little information to go on here. I wish I could read minds but unfortunately I can't.

    I am assuming that you mean "How do you caculate the length of belt in a roll?" and not how much belt is around a pulley.

    I use these formulas:

    When thickness of the belt is known:
    L = ((D*D)-(C*C)) / (15.3*t)
    L = Length; D = Outside Diameter (inches); C = Inside Diameter (inches); t = belt thickness (inches)

    When wraps are known:
    L = ((D+C)*3.14*n) / 24
    n = Number of wraps in roll
    Dear Mr.Gary Blenkhorn,

    Help us to understand the derivation of the above formulas.

    Thanks & regards,

  5. #5
    Teus Tuinenburg

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    L = ((Daverage)*3.14*n

    Daverage = (D+C)/2

    L = ((D+C)*3.14*n) / 2


    ( Instead of L = ((D+C)*3.14*n) / 24 )


    Example:
    C=1 m
    t = 0.005 m
    n = 50 wraps

    D = 1+2*n*0.005 = 1.5 m

    L = L = ((1.5+1)*3.14*50) / 2 = 196 m

    The formula:
    L = ((D*D)-(C*C)*3.14) / (48*t)

    should be:
    L = ((D*D)-(C*C)*3.14) / (4*t)

    example:
    L = ((1.5*1.5)-(1*1)*3.14) / (4*0.005) = 196 m

    Success
    Teus
    Last edited by Teus Tuinenburg; 30th April 2011 at 10:26. Reason: D=1.5, noticed by Mr sganesh. Thanks
    Teus

  6. #6
    Teus Tuinenburg

    Professional Experience 50 Years / 6 Month Teus Tuinenburg has 50 Years and 6 Month professional experience

    Discussions 1796 Teus Tuinenburg acceded to 1796 discussions, Articles 10 Teus Tuinenburg wrote 10 articles, Publications 0 Teus Tuinenburg Tuinenburg released 0 publications

    Searching Falsifications in my perception of pneumatic conveying

    Know-How conveying (1368) Teus Tuinenburg used this tag 1368 times, pneumatic conveying (1174) Teus Tuinenburg used this tag 1174 times, pneumatic (40) Teus Tuinenburg used this tag 40 times

    Dear sganesh,

    Lateral area of the coil is:

    Area = 3.14/4*(D*D - C*C) = L*t

    Resulting in:

    L = 3.14/4*(D*D - C*C) /t

    Mathematics can be simple.


    Have a nice day
    Teus
    Teus

  7. #7
    The 24 is used to convert the roll measured in inches into feet for the length of the roll. Thus 2*12 = 24. I should have stated that L = Length in Feet

    Imperial is sometimes more confusing than metric. But that is what I learned in school instead of metric.

    The 15.3 is dirived by 4/3.14(Pi)*12 (inches per foot).

    I think in imperial and not thinking about our Metric friends. Sorry for any confusion.

  8. #8
    Teus Tuinenburg

    Professional Experience 50 Years / 6 Month Teus Tuinenburg has 50 Years and 6 Month professional experience

    Discussions 1796 Teus Tuinenburg acceded to 1796 discussions, Articles 10 Teus Tuinenburg wrote 10 articles, Publications 0 Teus Tuinenburg Tuinenburg released 0 publications

    Searching Falsifications in my perception of pneumatic conveying

    Know-How conveying (1368) Teus Tuinenburg used this tag 1368 times, pneumatic conveying (1174) Teus Tuinenburg used this tag 1174 times, pneumatic (40) Teus Tuinenburg used this tag 40 times

    Dear Gary,

    Are you also driving on the left side in a metric country?

    Greetings
    Teus
    Teus

  9. #9
    Quote Originally Posted by Teus Tuinenburg View Post
    Dear Gary,

    Are you also driving on the left side in a metric country?

    Greetings
    Teus
    Teus

    The country may have gone metric but us old school guys didn't change. Unless it is a government project all designs are done in imperial. Maybe when us old guys are all dead and gone that may change.

    Funny thing is all building materials are still supplied in imperial. If you framed a house to the stud spacings as per the building code you would not be able to find a piece of plywood that would fit because they are sold as 48" x 96". Oh you could buy it in metric sizes but it would cost about 25% more.

    And no we do not drive on the left side, we drive on the RIGHT side. The correct side. haha

    Cheers,
    Gary

  10. Dear All,


    Thank you very much.

    regards


    Ramesh Kumar

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